Which of the following is correct increasing order of molecular mass?

H_{2} O < H C l < H_{2} S < {C O}_{2}

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H_{2} O < H_{2} S < H C l < C O_{2}

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H_{2} O < C O_{2} << H C l < H_{2} S

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H C l < H_{2} S < H_{2} O < {C O}_{2}

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Solution

The correct option is B $H_{2} O < H_{2} S < H C l < C O_{2}$
Atomic mass of $H = 1$

Atomic mass of $O = 16$

Atomic mass of $C l = 35.5$

Atomic mass of $C = 12$

Atomic mass of $S = 32$

Molecular mass of the given compounds are-

$H_{2} O = 2 + 16 = 18$

$H C l = 1 + 35.5 = 36.5$

$H_{2} S = 2 + 32 = 34$

$C O_{2} = 12 + 32 = 44$

Hence, the correct increasing order for the molecular mass is,
$H_{2} O < H_{2} S < H C l < C O_{2}$

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