Which of the following is correct order of bond angle?
$(1) N H_{3} > P H_{3} > N F_{3} (2) N F_{3} > N H_{3} > P H_{3}$
$(3) N H_{3} > N F_{3} > P H_{3} (4) P H_{3} > N H_{3} > N F_{3}$

Open in App

Solution

$(1) N H_{3} > P H_{3} > N F_{3}$
$N$ is a smaller central atom, and additionally, it is more electronegative. It attracts all the electrons closer to itself.

Suggest Corrections

Similar questions

P H_{3}, N H_{3}

N F_{3}, P F_{3}

N H_{3}

N F_{3}

P H_{3}

P F_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}

P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

Join BYJU'S Learning Program