Question

Which of the following is correct order of decreasing $S_{N}2$ reactivity?

• A. $R_{2}CHX>R_{3}CX>RC{H}_{2}X$
• B. $RC{H}_{2}X>R_{3}CX>R_{2}CHX$
• C. $RC{H}_{2}X>R_{2}CHX>R_{3}CX$
• D. $R_{3}CX>R_{2}CHX>RC{H}_{2}X$ (X = halogen)

Answer 1

The correct option is C $RC{H}_{2}X>R_{2}CHX>R_{3}CX$

Reactivity decreases as the steric hinderance increases for $S_{N}2$ reaction.