Which of the following is correct regarding the bond order in $S O_{4}^{2 -}$ ion?

3/2

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5/4

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4/3

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Solution

The correct option is A 3/2
Bond order = $\frac{Total number of bonds formed between two atoms in all structures}{Total number of resonating structures}$

There are a total 6 resonating structures of $S O_{4}^{2 -}$ .

Hence,
Bond order = $\frac{2 + 2 + 1 + 2 + 1 + 1}{6} = \frac{9}{6}$ = 3/2

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