Which of the following is correct regarding the reaction of fluorine with water ?
$2 F_{2} (g) + 2 H_{2} O (l) \to 4 H^{+} (a q) + 4 F^{-} (a q) + O_{2} (g)$

Fluorine is oxidised to

F^{-}

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Water is oxidised to

O_{2}

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Water is reduced to

H^{+}

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Oxidation state of fluorine does not change

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Solution

The correct option is B Water is oxidised to $O_{2}$
Flourine is reduced from $0$ to $- 1$ ,
water is oxidised from $- 2$ to $0$ .
An increase in oxidation state indicates oxidation of water to oxygen.

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Similar questions

O F_{2} & O_{2} F_{2}

H_{2} (g)

O_{2} (g)

O_{2} (g) + 2 H_{2} O (l) + 4 e^{-} \to 4 O H^{-} (a q)

H_{2} (g) + 2 O H^{-} (a q) \to 2 H_{2} O (l) + 2 e^{-}

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9650 sec

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