Question

Which of the following is correct?

$S{O}_3+HBr\to A+B+C$

Reddish Acidic Neutral

Brown Oxide compound

Coloured

Substance

• A. B can act as bleaching agent
• B. A can be starch iodide test
• C. B can oxidise $C{l}_2$
• D. A oxidises Hypo to $S_4{O}_6^{2-}$

Answer 1

The correct option is A B can act as bleaching agent

$S{O}_3+HBr\to B{r}_2+S{O}_2+H_{2}O$

Here,

$B{r}_2=$ Reddish brown colour $\left(A\right)$

$S{O}_2=$ Acidic oxides $\left(B\right)$

$H_{2}O=$ Neutral compound $\left(C\right)$

Here $S{O}_2$ can be used as bleaching agent. The bleaching action of $S{O}_2$ is due to the reducing action of $S{O}_2$. The coloured impurities in presence of $S{O}_2$ get reduced to the colourless impurities.