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Question

Which of the following is correct trend for electron affinity in halogens?

A
F<Cl<Br<I
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B
F>Cl>Br>I
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C
F<Cl>Br>I
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D
Cl>Br>I>F
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Solution

The correct option is C F<Cl>Br>I
The amount of energy released when an extra electron is added to an isolated gaseous atom is called electron affinity.
Down the group effective nuclear charge experienced by the valence electrons decreases. So the order of electron affinity will be Cl>Br>I.
Since fluorine is very small and it does not accomodate an incoming electron to its valence shell due to interelectronic repulsion.
So order becomes Cl>F>Br>I or F<Cl>Br>I

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