Question

Which of the following is correct value of $x$ in $Cr(CO{)}_x$?

• A. $2$
• B. $4$
• C. $6$
• D. Unpredictable

Answer 1

The correct option is C $6$

Given, $Cr(CO{)}_x$

Here, $Cr$ has zero oxidation state,

as has zero oxidation state in the compound

So at zero oxidation state the Electronic configuration of $Cr$ is

$\left[Ar\right]4s^{\prime }3d^5$

that means $Cr$ has $6$ valencies, as $Cr$ in this state is stable due to half filled orbitals.

Now, for $6$ valencies, $6$ $CO$ is required.

Therefore $x=6$

The compound is $Cr(CO{)}_6$