Question

Which of the following is correctly represents increasing order of reducing nature of hydrides?

• A. $H_{2}Se<H_{2}S<H_{2}Te$
• B. $H_{2}Te<H_{2}Se<H_{2}S$
• C. $H_{2}S<H_{2}Se<H_{2}Te$
• D. $H_{2}S<H_{2}Se>H_{2}Te$

Answer 1

Answer: (C)

$H_{2}S<H_{2}Se<H_{2}Te$

As the size of the atom increase, the H-e bond become weaker and H is released from the corresponding hydride more easily .as a result of that, reducing character also increases, so the correct order is

$H_{2}S<H_{2}Se<H_{2}Te$