Question

Which of the following is equal to 1?

• A. $2^0+3^0+4^0$
• B. $2^0\times 3{}^0\times 4^0$
• C. $(3^0–2^0)\times 4^0$
• D. $(3^0–2^0)\times (3^0+2^0)$

Answer 1

The correct option is B

$2^0\times 3{}^0\times 4^0$

Determine the equation that's valued is equal to 1.

For point A)

$$\begin{gathered} 2^0+3^0+4^0=1+1+1;a^0=1 \\ \Rightarrow =3 \end{gathered}$$

For point B)

$$\begin{gathered} 2^0\times 3^0\times 4^0=1\times 1\times 1;a^0=1 \\ \Rightarrow =1 \end{gathered}$$

For point C)

$$\begin{gathered} (3^0-2^0)\times 4^0=(1-1)\times 1;a^0=1 \\ \Rightarrow =0\times 1 \\ \Rightarrow =0 \end{gathered}$$

For point D)

$$\begin{gathered} (3^0-2^0)\times (3^0+2^0)=(1-1)\times (1+1);a^0=1 \\ \Rightarrow =0\times 2 \\ \Rightarrow =0 \end{gathered}$$

Hence, the correct choice is “Option B”.