Which of the following is equivalent to x - 3 - 4x 3x - 1 -

The correct option is A 3(x 4)x The value of (x 3 4x) (3(x+1)) = x ^ 2 3x 4 x × 3 x+1 = (x+1)(x 4) x × 3 x+1 = 3(x 4) x ...

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Byju's Answer

Standard VII

Mathematics

(a + b)^2 Expansion and Visualisation

Which of the ...

Question

Which of the following is equivalent to $(x - 3 - \frac{4}{x}) (\frac{3}{x + 1})$ ?

\frac{3 (x - 4)}{x}

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2 x - 4

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\frac{- 6 (x + 2)}{x + 1}

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- 7

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- 12

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Solution

The correct option is A $\frac{3 (x - 4)}{x}$
The value of $(x - 3 - \frac{4}{x}) (\frac{3}{(x + 1)})$
$= \frac{x^{2} - 3 x - 4}{x} \times \frac{3}{x + 1}$
$= \frac{(x + 1) (x - 4)}{x} \times \frac{3}{x + 1}$
$= \frac{3 (x - 4)}{x}$

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$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$