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B
x < 5
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C
1 < x <5
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D
x > -1
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Solution
The correct option is C1 < x <5 We know that if |x|<a, then we can write it as –a<x<a Therefore |x−3|<2 can be written as −2<x−3<2 Add 3 on each side −2+3<x−3+3<2+3 1<x<5 The correct answer is option C.