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Question

Which of the following is formed in the solution when [Cu(NH3)4]2+ is treated with KCN till the colour of the complex is discharged?

A
Cu(CN)2
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B
[Cu(CN)4]2
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C
[Cu(CN)4]3
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D
[Cu(CN)6]4
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Solution

The correct option is A [Cu(CN)4]3
Addition of KCN to CuSO4 solution first causes reduction and then precipitates CuCN (cuprous cyanide). This reacts with excess CN, forming a soluble four co-ordinate complex [Cu(CN)4] which is tetrahedral in shape.
2Cu2++4CN2CuCN+(CN)2
Cyanogen
CuCN+3CN[Cu(CN)4]3
Colourless complex

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