You visited us 1 times! Enjoying our articles? Unlock Full Access!

Bronsted Lowry Theory

Which of the ...

Question

Which of the following is formed, when $H S^{-}$ acts as a Bronsted base ?

S^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} S_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{3} S^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $H_{2} S$
When $H S^{-}$ acts as a Bronsted base, it reacts with $H^{+}$ (proton) to form hydrogen sulphide $(H_{2} S)$ .
$H S^{-} + H^{+} \to H_{2} S$

Suggest Corrections

Similar questions

H S^{-}, H_{3} O^{+}, H_{2} {P O}_{4}^{-}, H {S O}_{4}^{-}, H F, {C H}_{3} C O O H, C_{6} H_{5} O H, H C l O_{4}, {N H}_{4}^{+}

{O H}^{-}, {C H}_{3} C O O^{-}, {C l}^{-}, {C O}_{3}^{2 -}, H_{2} {P O}_{4}^{-}, {C H}_{3} {N H}_{2}, {C H}_{3} C O O H, {N H}_{2}^{-}

H_{2} O, H {C O}_{3}^{-}, H_{2} {S O}_{4}, H_{3} {P O}_{4}, H S^{-}, {N H}_{3}

H C l, H I; H_{2} {C O}_{3}, H_{2} {S O}_{4}; H_{2} O, H_{2} S; C_{2} H_{5} O H, C_{6} H_{5} O H

{O H}^{-}, {C l}^{-}; {O H}^{-}, {N H}_{2}^{-}; {O H}^{-}, {C H}_{3} C O O^{-}; {C H}_{3} C O O^{-}, {C l}^{-}; {N H}_{3}, {C H}_{3} {N H}_{2}

S^{2 -}, H^{+}, {O H}^{-}, B F_{3}, {N i}^{2 +}, N F_{3}, A l {C l}_{3}, S n {C l}_{4}, {N H}_{3}, {({C H}_{3})}_{2} O

{H C O_{3}}^{-}

C H_{3} C H_{2} O H

H_{2} P O_{4}^{-}

K_{a 1}, K_{a 2}

K_{a 3}

H_{2} S ⇌ H^{+} H S^{-}

H S^{-} ⇌ H^{+} S^{2 -}

H_{2} S ⇌ 2 H^{+} S^{2 -}

K_{a 1}, K_{a 2}

K_{a 3}

Join BYJU'S Learning Program