Question

Which of the following is formed when n-butyl lithium reacts with tin (II) chloride?

• A. $LiBr$
• B. $E{t}_{4}Pb$
• C. $(C_4{H}_9{)}_{4}Sn$
• D. $(C_2{H}_5{)}_{4}Pb$

Answer 1

The correct option is C $(C_4{H}_9{)}_{4}Sn$

n-butyl lithium reacts with tin(IV) chloride to form tetra butyl tin.
$4BuLi+SnC{l}_4\to (Bu{)}_{4}Sn+4LiCl$