Which of the following is Friedel-Crafts reaction?

$C_{6} H_{6} C l_{2} - ------- \to anhyd. F e C l_{3} C_{6} H_{6} C l$

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$C_{6} H_{5} C H O + C H_{3} C H O d i l . K O H - ---- \to Δ C_{6} H_{5} C H = C H - C H O$

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$C_{6} H_{6} C H_{3} C O C l - ------- \to a n h y d . F e C l_{3} C_{6} H_{6} - C H_{3} - O | | C - C H_{3}$

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$C_{6} H_{5} O H C H C l_{3} - --- \to K O H Salicylaldehyde$

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Solution

The correct option is C
$C_{6} H_{6} C H_{3} C O C l - ------- \to a n h y d . F e C l_{3} C_{6} H_{6} - C H_{3} - O | | C - C H_{3}$

Friedel-crafts reactions:

$C_{6} H_{6} (Benzene) C H_{3} C O C l - ------- \to a n h y d . F e C l_{3} C_{6} H_{6} - O | | C - C H_{3} (Acetophenone)$

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Which of the following statements regarding Friedel-Crafts reactions is wrong?

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