Question

Which of the following is incorrect about trigonal hybridisation?

• A. It originates from the mixing of one $s$ and two $p$ orbitals
• B. Carbon containing one double bond exhibits this type of hybridisation
• C. All the hybrid orbitals remain in one plane
• D. $B{H}_3$ and $N{H}_3$ show this hybridisation

Answer 1

The correct option is D $B{H}_3$ and $N{H}_3$ show this hybridisation

$s{p}^2$ hybridisation is also called trigonal hybridisation. It originates from the mixing of one $s$ and two $p$ orbitals and produces three equivqlent hybrid orbitals. The hybrid orbitals make an angle of ${120}^o$ and remains in one plane.
A carbon containing double bond is $s{p}^2$ hybridised.
All compounds of boron show this hybridistion i.e., $B{F}_3,B{H}_3$, etc,.
$N{H}_3$ molecule shows $s{p}^3$ hybridisation.