The correct option is D Formation of III involves E1 reaction
Rate of formation of II and IV are similar because it goes by substitution reaction where C−H and C−D bond breaking is not involved.
I and III are products of elimination reaction where C−H and C−D bond breaking is the part of RDS.
Breaking of C−D bond is difficult compare to C−H due to higher mass of D.
Hence, rate in I is slower than III due to isotopic effect of D
It undergo via E2 not E1 because carbocation is not stable and alcoholic KOH is a strong base.