Which of the following is iso-electronic?

C O_{2}, N O_{2}

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{N O_{2}}^{-}, C O_{2}

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C N^{-}, C O

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S O_{2}, C O_{2}

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Solution

The correct option is C $C N^{-}, C O$
Isoelectronic species have an equal number of electrons.
Here $C N^{-}$ have $14$ electrons out of which $6$ are provided by $C$ , $7$ by $N$ and one negative charge.
Also, $C O$ contain $14$ electron as $6$ electrons are provided by $C$ and $8$ electrons are present in $O$ .
Thus, $C N^{-}$ and $C O$ are isoelectronic.

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S O_{2}, C O_{2}, N_{2} O, O F_{2}, {I C l_{2}}^{-}, {I_{3}}^{-}, N O_{2}, {N O_{2}}^{-}, {N O_{2}}^{+}, {B F_{2}}^{-}, B e C l_{2}, {N_{3}}^{-}, H C N .

Which of the following are iso-electronic and iso-structural?

$N O_{3}^{-}$ , $C O_{3}^{2 -}$ , $C l O_{3}^{-}$ , $S O_{3}$

C o^{2 +} + N O_{2}^{-} + H^{+} \to C o^{3 +} + N O + H_{2} O

N O_{2} + C O \to N O + C O_{2}

S t e p I N O_{2} + N O_{2} k_{1}, s l o w - --- \to N O_{3} + N O

S t e p I I N O_{3} + C O k_{2}, f a s t - --- \to N O_{2} + C O_{2}

(\frac{d x}{d t})

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