Which of the following is not a linear molecule?

$N O_{2}$

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I (C N)_{2}^{-}

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$I_{3}^{-}$

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$C_{2} (C N)_{2}$

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Solution

The correct option is A $N O_{2}$

$I_{3}^{-}$ is a linear molecule.

Consider Iodine with an extra electron as the central atom which makes a covalent bond with the other iodine atoms. Now the central atom has two bond pairs and three lone pairs.
$t o t a l e l e c t r o n p a i r s = 5$
The hybridisation is $s p^{3} d$ . The geometry is trigonal bi-pyramidal with all the lone pairs at equatorial positions.

$I (C N)_{2}^{-}$ is also linear.

Consider Iodine as the central atom with an extra electron, forming a covalent bond with the two $C N$ . So iodine has two bond pairs and and three lone pairs.
$t o t a l e^{-} p a i r s = 5$
The hybridisation is $s p^{3} d$ . The geometry is trigonal bi-pyramidal with three lone pairs at equatorial positions.

$C_{2} (C N)_{2}$ is a linear molecule

$C N - C \equiv C - C N$

$N O_{2}$ is a bent molecule.

The lewis structure of $N O_{2}$ is represented as:

In the structure, the nitrogen atom is doubly bonded to one oxygen and the other oxygen that carries an extra electron makes a co-ordinate bond with nitrogen. Thus, nitrogen has one electron less than the number of electrons required for a stable octet state and thus carries a formal positive charge.
It is $s p^{2}$ hybridized and has a bent structure because of lone pair - bond pair repulsions.

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