Which of the following is not a solution of the pair of equations $3 x - 2 y = 4$ and $9 x - 6 y = 12$

x = 2

y = 1

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x = 4

y = 4

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x = 6

y = 7

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x = 5

y = 3

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Solution

The correct option is C $x = 5$ , $y = 3$
Equations are $3 x - 2 y = 4$ and $9 x - 6 y = 12$
Here option D doesnot satisfy both the equations
Putting $x = 5$ and $y = 3$ in the above equations, we get
$3 (5) - 2 (3) = 9 \neq 4$ and
$9 (5) - 6 (3) = 27 \neq 12$

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Similar questions

Solve the following pair of linear equations by the elimination method and the substitution method :

(i) x+y=5 and 2x−3y=4
(ii) 3x+4y=10 and 2x−2y=2
(iii) 3x−5y−4=0 and 9x=2y+7
(iv) x2+2y3=−1 and x−y3=3

\frac{1}{2 x} - \frac{1}{y} = - 1

\frac{1}{x} + \frac{1}{2 y} = 8

x \neq 0 a n d y \neq 0)

2 x + 3 y = 2; x - \frac{y}{2} = \frac{1}{2}

\frac{1}{2 x} - \frac{1}{y} = - 1

\frac{1}{x} + \frac{1}{2 y} = 8

x \neq 0, y \neq 0)

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