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B
(p⇒q)⇒(∼q⇒∼p)
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C
p∨∼(q∧∼q)
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D
p∧(q∨∼q)
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Solution
The correct option is Dp∧(q∨∼q) A tautology is a statement which is always true. p∧(q∨∼q) is false when p is false. Hence, it is not a tautology. Other statements are always true.