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Electronic Configuration

Which of the ...

Question

Which of the following is NOT changed of Xe in given reaction?
$2 X e O F_{4} + S i O_{2} \to 2 X e O_{2} F_{2} + S i F_{4}$

Hybridisation of Xe

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Number of d-orbital(s) is hybridisation

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Number of

O - X e - F

bond angle

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Covalency of Xe

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Solution

The correct option is D Covalency of Xe
$2 X e O F_{4} + S i O_{2} ⟶ 2 X e O_{2} F_{2} + S i F_{4}$
Covalency of $X e O F_{4}$ is 6(refer to image 01)
Covalency of $X e O_{2} F_{2}$ is 6(refer to image 02)
So, covalency of $X e$ is 6 which donot change.

Suggest Corrections

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