Question

Which of the following is not electron deficient ?

• A. $N{H}_3$
• B. $B{F}_3$
• C. $AlC{l}_3$
• D. $B{H}_3$

Answer 1

The correct option is A $N{H}_3$

In $N{H}_3$, nitrogen's electronic configuration is $1s^{2}2s^{2}2p^6$ so there is no empty orbital. So $N{H}_3$ is not electronic deficient.

In $B{F}_3$, boron's electronic configuration is $1s^{2}2s^{2}2p_x^{2}2p_y^{2}2p_z^0$. One orbital that is $2p_z^0$ is completely empty, so $B{F}_3$ is electron deficient.

In $AlC{l}_3$, aluminium's electronic configuration is $\left[Ne\right]3s^{2}3p_x^{2}3p_y^{2}3p_z^0$. One orbital that is $2p_z^0$ is completely empty, so $AlC{l}_3$ is electron deficient.

In $B{H}_3$, boron's electronic configuration is $1s^{2}2s^{2}2p_x^{2}2p_y^{2}2p_z^0$. One orbital that is $2p_z^0$ is completely empty, so $B{H}_3$ is electron deficient.

So answer is A.