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B
XeF4
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C
XeOF4
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D
CH3Cl
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Solution
The correct options are AXeF2 BXeOF4 DCH3Cl Molecules with one central atom surrounded by four can have square planar shape. Therefore XeF2, XeOF4 cannot have square planar shape.
In CH3Cl it is sp3 hybrid C, therefore, its tetrahedral. Only XeF4 has square planar shape and octahedral geometry.