Which of the following is not tetrahedral in shape?

N H_{4}^{+}

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S i C l_{4}

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S F_{4}

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S O_{4}^{2 -}

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Solution

The correct option is C $S F_{4}$
The hybridization of S in $S F_{4}$ is $S p^{3} d$ and the shape is trogonal bipyramidal due to the presence of lonepair on sulfur.So its not tetrahedral.
Hence option C is correct.

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Similar questions

S O_{4}^{2 -}

S F_{4}

S F_{2}

s p^{3}

Assertion: A molecule of silicon tetrachloride ( $S i C l_{4}$ ) is nonpolar.

Reason: The four bonds in $S i C l_{4}$ are identical and the molecule has a tetrahedral structure.

S O_{4}^{2 -} and C r O_{4}^{2 -}

S i C l_{4} and T i C l_{4}

N H_{3} and N O_{3}^{-}

B C l_{3} and B r C l_{3}

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