The correct option is B (25,12)
log(52−1x) is defined when x>25....(1)
Similarly, logx is defined when x>0....(2)
From (1) and (2), we get x>25.....(3)
Now, log(52−1x)>logx
⇒52−1x>x
⇒2x2−5x+2<0
(2x−1)(x−2)<0
x∈(12,2)
Hence option C is not the solution of the given equation.