Which of the following is not nbsp-true-a - b-2 - a-2 - 2ab - b-2-x nbsp- a-x -b- - nbsp-x-2- -a -b-x - ab-a - b-2 - a-2 - 2ab - b-2-a - b-2- b-2 - 2ab - a-2-

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Application of Algebraic Identities

Which of the ...

Question

Which of the following is not true?

${(a - b)}^{2}$ = $a^{2}$ - 2ab + $b^{2}$

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$(x + a) (x + b) = x^{2} + (a + b) x + a b$

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${(a + b)}^{2} = b^{2}$ + 2ab + $a^{2}$

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${(a + b)}^{2}$ = $a^{2}$ - 2ab + $b^{2}$

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Solution

The correct option is D
${(a + b)}^{2}$ = $a^{2}$ - 2ab + $b^{2}$

The following are the correct identities.

${(a - b)}^{2}$ = $a^{2}$ - 2ab + $b^{2}$

$(x + a) (x + b) = x^{2} + (a + b) x + a b$

${(a + b)}^{2}$ = $b^{2}$ + $2 a b$ + $a^{2}$

But, ${(a + b)}^{2}$ is not equal to
$a^{2}$ - 2ab + $b^{2}$ .

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Similar questions

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

Q. Simplify:
(a² + b² + 2ab) − (a² + b² −2ab)

If a + b + c = 2s, then prove the following identities

(a) s² + (s − a)² + (s − b)² + (s − c)² = a² + b² + c²

(b) a² + b² − c² + 2ab = 4s (s − c)

(d) a² − b² − c² + 2ab = 4(s − b) (s − c)

(e) (2bc + a² − b² − c²) (2bc − a² + b² + c²) = 16s (s − a) (s − b) (s − c)

(f)

(a - b) x + (a + b) y = a^{2} - 2 a b - b^{2}, (a + b) (x + y) = a^{2} + b^{2} .

Q. Question 3

Which of the following is correct?
a)

(a - b)^{2} = a^{2} + 2 a b - b^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(a - b)^{2} = a^{2} - b^{2}

(a + b)^{2} = a^{2} + 2 a b - b^{2}

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Which of the following is not true?

The correct option is D (a+b)2 = a2 - 2ab + b2 The following are the correct identities. (a−b)2 = a2 - 2ab + b2 (x+a)(x+b)=x2+(a+b)x+ab (a+b)2 = b2 + 2ab + a2 But, (a+b)2 is not equal to a2 - 2ab + b2.