Which of the following is not true as far as $B F_{3}$ is concerned?

Electron deficient

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Lewis acid

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Ionic compound

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Covalent compound

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Solution

The correct option is C Ionic compound
$B F_{3}$ has boron bonded with three fluorine through covalent bonds.
Boron has an incomplete octet, so the compound is electron deficient.
It accepts a pair of an electron to complete its octet, so it is a $L e w i s$ $a c i d$ .

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B F_{3}

(C H_{3})_{2} O + B F_{3} \to (C H_{3})_{2} O \to B F_{3}

(S i H_{3})_{2} O + B F_{3} \to (S i H_{3})_{2} O \to B F_{3}

H_{3} N + B F_{3} \to H_{3} N \to B F_{3}

(C H_{3})_{2} O + B F_{4}^{-} \to (C H_{3})_{2} O \to B F_{4}^{-}

B F_{3}

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