Which of the following is not true for the figure below?

AC ⊥ BD

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BC = CD

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∠ADB = ∠ ABD

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∠DAB = ∠ DCB

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Solution

The correct option is D
∠DAB = ∠ DCB

Its a kite. According to the properties of a kite:
AC $⊥$ BD
$\Rightarrow$ BC = CD
In $△ A B D$ , AB = AD
$∠ A D B$ = $∠ A B D$
But, $∠ D A B$ $\neq$ $∠ D C B$

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