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Question

Which of the following is not true for this progressive wave y=4sin2π(t0.02x100) where y and x are in cm & t in sec. [CMPT 2003]

A
Its amplitude is 4 cm
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B
Its wavelength is 100 cm
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C
Its frequency is 50 cycles/sec
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D
Its propagation velocity is 50×103 cm/sec
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Solution

The correct option is D Its propagation velocity is 50×103 cm/sec
The standard equation of a wave is given by,
y=Asin(ωtkx)

Let's now convert the given equation into the standard wave equation.
y=4sin2π(t0.02x100)

or, y=4sin(2π0.02t2π100x)

Comparing this with the standard equation we get,
A=4,ω=2π0.02,k=2π100

Amplitude is 4cm which is true, so option (A) is correct.

Wavelength, λ=2πk=2π2π100=100cm. So, option (B) is also correct.

Frequency, f=ω2π=2π0.022π=50cycles/sec. So, option (C) is also correct.

The propagation velocity, v=ωk=2π0.022π100=5000cm/s=50×102cm/s. Hence option (D) is not true for this wave.
Hence Option is D

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