Which of the following is oxidation state of a lead?

+ 2, + 4

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+ 1, + 2

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+ 3, + 4

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+ 4

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Solution

The correct option is C $+ 2, + 4$
Lead shows two types oxidation states
$+ 2$ oxidation state which is lower oxidation state due to inert pair effect(stable oxidation state for lead).
$+ 4$ oxidation state which is Higher oxidation state
Hence option $A$ is correct.

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