Which of the following is pseudo alum?

(N H_{4})_{2} S O_{4} \cdot F e_{2} (S O_{4})_{3} \cdot 24 H_{2} O

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K_{2} S O_{4} \cdot A l_{2} (S O_{4})_{3} \cdot 24 H_{2} O

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M n S O_{4} \cdot A l_{2} (S O_{4})_{3} \cdot 24 H_{2} O

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None of these

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Solution

The correct option is D $M n S O_{4} \cdot A l_{2} (S O_{4})_{3} \cdot 24 H_{2} O$
A pseudo alum is a double sulfate of the typical formula $A S O_{4} B_{2} (S O_{4})_{3} 24 H_{2} O$ ,
where A is a divalent metal ion, such as cobalt (wupatkiite), manganese (apjohnite), magnesium (pickingerite) or iron (halotrichite or feather alum), and B is a trivalent metal ion. i.e. class of alums in which the usual monovalent metal of a true alum is replaced by a bivalent metal.
so $M n S O_{4} \cdot A l_{2} (S O_{4})_{3} \cdot 24 H_{2} O$ is pseudo alum.

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