The correct option is D Cu2O+12Cu2S→2Cu+12SO2
The sulphide ores of certain less electropositive metals like those of Hg, Pb, Cu, etc. when heated in air bring about the conversion of a part of the sulphide ore to oxide or sulphate which then reacts with the remaining sulphide to give the matal and SO2. No external reducing agent is used in this process.
2Cu2S+3O2→2Cu2O+3SO2
2Cu2O+Cu2S→6Cu+SO2