Which of the following is tetrahedral paramagnetic complex?

K_{2} [{P t C l}_{4}]

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K_{2} [{M n C l}_{4}]

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K_{2} [{Z n C l}_{4}]

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K_{2} [{H g l}_{4}]

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Solution

The correct option is D $K_{2} [{M n C l}_{4}]$
Complex $K_{2} [M n C l_{4}]$ is tetrahedral and paramagnetic in nature because Mn is having +2 oxidation state and hence will have $3 d^{5} 4 s^{0}$ configuration. Also $C l^{-}$ is a weak field ligand and hence pairing of electrons won't take place. Therefore The hybridization is $s p^{3}$ and is paramagnetic in nature.

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$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$ have equilibrium constants $K_{1}$ and $K_{2}$ respectively

at 298K. Which of the following relationships between $K_{1}$ and $K_{2}$ is correct

Equilibrium constants $K_{1}$ and $K_{2}$ for the following equilibria are

$N O (g) + 0.5 O_{2} (g) \to K_{1} N O_{2} (g)$ and
$2 N O_{2} (g) \to K_{2} 2 N O (g) + O_{2} (g)$

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