Question

Which of the following is the correct form of Schrodinger wave equation?

• A. $\frac{{\partial }^2\Psi }{{\partial }^{2}x}+\frac{{\partial }^2\Psi }{{\partial }^{2}y}+\frac{{\partial }^2\Psi }{{\partial }^{2}z}+\frac{8{\pi }^{2}m}{h^2}(E-V)\Psi =0$
• B. $\frac{{\partial }^2\Psi }{\partial x^2}+\frac{{\partial }^2\Psi }{\partial y^2}+\frac{{\partial }^2\Psi }{\partial z^2}+\frac{8{\pi }^{2}m}{h^2}(E-V)\Psi =0$
• C. $\frac{\partial {\Psi }^2}{\partial x^2}+\frac{\partial {\Psi }^2}{\partial y^2}+\frac{\partial {\Psi }^2}{\partial z^2}+\frac{8{\pi }^{2}m}{h^2}(E-V)\Psi =0$
• D. $\frac{{\partial }^2\Psi }{\partial x^2}+\frac{{\partial }^2\Psi }{\partial y^2}+\frac{{\partial }^2\Psi }{\partial z^2}+\frac{8{\pi }^2{m}^2}{h^2}(E-V)\Psi =0$

Answer 1

The correct option is B $\frac{{\partial }^2\Psi }{\partial x^2}+\frac{{\partial }^2\Psi }{\partial y^2}+\frac{{\partial }^2\Psi }{\partial z^2}+\frac{8{\pi }^{2}m}{h^2}(E-V)\Psi =0$

Schrodinger wave equation is:

$\frac{{\partial }^2\Psi }{\partial x^2}+\frac{{\partial }^2\Psi }{\partial y^2}+\frac{{\partial }^2\Psi }{\partial z^2}+\frac{8{\pi }^{2}m}{h^2}(E-V)\Psi =0$.

The Schrödinger equation is a partial differential equation that describes the dynamics of quantum mechanical systems via the wave function. The trajectory, the positioning, and the energy of these systems can be retrieved by solving the Schrödinger equation.