Which of the following is the correct increasing order of boiling point of the following compounds?
I) $C H_{3} - C H_{2} - C H_{2} - O H$
II) $C H_{3} - C H | O H - C H_{3}$
III) $C H_{3} - O - C H_{2} - C H_{3}$

l l < l < l l l

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l l l < l l < l

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l < l l < l l l

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l l < l l l < l

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Solution

The correct option is B $l l l < l l < l$
We know that Primary alcohols have a higher boiling point than Secondary alcohols. Again, due to intermolecular Hydrogen bonding, alcohols, in general, have a much higher boiling point than ethers.
Thus, the correct order is $I I I < I I < I$
Hence, option $B$ is the correct answer.

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Similar questions

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

C H_{3} - C H O, C H_{3} - C H_{2} - O H, C H_{3} - C H_{2} - C H_{3}

H - X

C H_{2} = C H - O H

C H_{2} = C H - C H_{2} O H

C H_{3} - C H_{2} - O H

C H_{3} - C H | O H - C H_{3}

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