Question

Which of the following is the correct match with respect to the given question ?
'ABCD' is a rhombus such that $\angle ACB={40}^o$ then $\angle ADB=$____.

${70}^o$	As $\angle ADB=1/2({180}^o-{40}^o)$
${45}^o$	$\angle C+\angle D={90}^o$
${50}^o$	$\angle BCD={80}^o\Rightarrow \angle ADC={100}^o\therefore \angle ADB=\left(1/2\right)x{100}^o$
${60}^0$	All sides are equal

• A. $\left(a\right)\to \left(i\right)$
• B. $\left(c\right)\to \left(iii\right)$
• C. $\left(d\right)\to \left(iii\right)$
• D. $\left(b\right)\to \left(iv\right)$

Answer 1

Answer: (B)

$\left(c\right)\to \left(iii\right)$

The diagonal in a rhombus are perpendicular
So $\angle BPC={90}^0$
From triangle BPC the sum of angle is 180
SO $\angle CBP=180-40-90={50}^0$
Since triangle ABC is isosceles
We have AB=AC
SO$\angle ACB=\angle CAB={40}^0$
Again from triangle APB
So $\angle PBA$=180-40-90=50*.