Which of the following is the correct order for solubility in water?

N a S i O_{4} < K C l O_{4}

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N a B F_{4} < N a F

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M g S O_{4} < S r S O_{4}

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All of the above

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Solution

The correct option is B $N a B F_{4} < N a F$
In water, $N a F$ is more soluble than $N a B F_{4}$ due to higher hydration energy of small fluoride ion compared to that of large $B F_{4}^{-}$ ion.

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