Question

Which of the following is the correct order of decreasing oxidizing power of perhalates?

• A. $Br{O}_4^{-}>I{O}_4^{-}>Cl{O}_4^{-}$
• B. $I{O}_4^{-}>Br{O}_4^{-}>Cl{O}_4^{-}$
• C. $Br{O}_4^{-}>Cl{O}_4^{-}>I{O}_4^{-}$
• D. $Cl{O}_4^{-}>Br{O}_4^{-}>I{O}_4^{-}$

Answer 1

The correct option is A

$Br{O}_4^{-}>I{O}_4^{-}>Cl{O}_4^{-}$

$Br{O}_4^{-}\left(1.8V\right)>I{O}_4^{-}\left(1.64V\right)>Cl{O}_4^{-}\left(1.23V\right)$

The oxidizing power of perhalates can be explained on the basis of electrode potentials. The higher or more positive the reduction potential, the greater is its oxidizing power.