Question

Which of the following is the correct order of decreasing $S{N}^2$ reactivity

• A. $R_{2}CHX>R_{3}CX>RC{H}_{2}X$
• B. $RC{H}_{2}X>R_{3}CX>R_{2}CHX$
• C. $RC{H}_{2}X>R_{2}CHX>R_{3}CX$
• D. $R_{3}CX>R_{2}CHX>RC{H}_{2}X$

Answer 1

The correct option is C

$RC{H}_{2}X>R_{2}CHX>R_{3}CX$

$1^{o}R-X>2^{o}R-X>3^{o}R-X$