Which of the following is the correct order of the rate of reaction of $C_{6} H_{6}, C_{6} D_{6}$ and $C_{6} T_{6}$ towards nitration?

C_{6} H_{6} > C_{6} D_{6} > C_{6} T_{6}

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C_{6} H_{6} = C_{6} D_{6} = C_{6} T_{6}

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C_{6} H_{6} > C_{6} D_{6} = C_{6} T_{6}

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C_{6} T_{6} > C_{6} D_{6} > C_{6} H_{6}

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Solution

The correct option is B $C_{6} H_{6} = C_{6} D_{6} = C_{6} T_{6}$
The rates of nitration of $C_{6} H_{6}$ , $C_{6} D_{6}$ and $C_{6} T_{6}$ are the same.
The rate-determining step for nitration through Electrophilic Aromatic Substitution is the attack of the electrophile( $N O_{2}^{+}$ ) on the aromatic substrate.
Thus changing the H atoms to its isotopes will not affect the reaction at all. The change of these atoms affects the reaction only when the breakage of these $C - H / D / T$ bonds is a part of the rate determining step.

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