Which of the following is the correct product for the compound when treated with $B r_{2} / C C l_{4}$

C H_{3} - C H = C H_{2} \to C H_{3} - C H_{2} - C H_{2} B r

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C H_{3} - C H = C H_{2} \to B r C H_{2} - C H = C H_{2}

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C H_{3} - C H = C H_{2} \to C H_{3} - C H B r - C H_{3}

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C H_{3} - C H = C H_{2} \to C H_{3} - C H B r - C H_{2} B r

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Solution

The correct option is D $C H_{3} - C H = C H_{2} \to C H_{3} - C H B r - C H_{2} B r$
propene reacts with $B r_{2} / C C l_{4}$ to form 1,2-dibromo propane.
$C H_{3} C H = C H_{2} + B r_{2} / C C l_{4} \to C H_{3} C H B r C H B r$
propene 1,2-dibromo propane
So answer is D.

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Q. A hydrocarbon, 'X'

(C_{3} H_{4})

decolourises

B r_{2} / C C l_{4}

solution forming 'Y'. 'X' gave a red precipitate of a compound 'Z' with ammoniacal cuprous chloride.
X, Y, and Z respectively are:

Q. Identify the type of the following reaction of carbon compounds.
a. CH₃ -CH₂ -CH₂-OH → CH₃ -CH₂ -COOH
b. CH₃ -CH₂ -CH₃ → 3CO₂ + 4H₂O
c. CH₃ -CH = CH -CH₃ + Br₂ → CH₃ -CHBr - CHBr -CH₃
d. CH₃ -CH₃ + Cl₂→ CH₃ -CH₂ -Cl + HCl
e. CH₃-CH₂ -CH₂ -CH₂ -OH → CH₃ -CH₂ -CH=CH₂ + H₂O
f. CH₃-CH₂ -COOH + NaOH → CH₃ -CH₂ -COO - Na⁺ + H₂O
g. CH₃ -COOH + CH₃ -OH → CH₃ -COO- CH₃ + H₂O

C H_{3} - C H = C H_{2} + H B r \to

-------- the product is

Which are free radical reactions

$I . C H_{3} - C H = C H_{2} + H B r P e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} B r I I . C H_{3} - C H = C H_{2} + H B r \to C H_{3} - C H B r - C H_{3} I I I . C H_{3} - C H = C H_{2} + C l_{2} \to C l C H_{2} - C H = C H_{2} I V . C H_{3} - C H_{3} + C l_{2} \to C l C H_{2} - C H_{3}$

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

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Which of the following is the correct product for the compound when treated with Br2/CCl4

The correct option is D CH3−CH=CH2→CH3−CHBr−CH2Brpropene reacts with Br2/CCl4 to form 1,2-dibromo propane.CH3CH=CH2+Br2/CCl4→CH3CHBrCHBr propene 1,2-dibromo propaneSo answer is D.

Which of the following is the correct product for the compound when treated with $B r_{2} / C C l_{4}$

The correct option is D $C H_{3} - C H = C H_{2} \to C H_{3} - C H B r - C H_{2} B r$
propene reacts with $B r_{2} / C C l_{4}$ to form 1,2-dibromo propane.
$C H_{3} C H = C H_{2} + B r_{2} / C C l_{4} \to C H_{3} C H B r C H B r$
propene 1,2-dibromo propane
So answer is D.