Which of the following is the correctly balanced chemical equation?

C a (O H)_{2}

H F

⟶

2 H_{2} O

C a F_{2}

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C a (O H)_{2}

H F

⟶

2 H_{2} O

2 C a F_{2}

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C a (O H)_{2}

2 H F

⟶

2 H_{2} O

2 C a F_{2}

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C a (O H)_{2}

2 H F

⟶

2 H_{2} O

C a F_{2}

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Solution

The correct option is D $C a (O H)_{2}$ + $2 H F$ $⟶$ $2 H_{2} O$ + $C a F_{2}$
In the balanced equation, number of each atoms on reactant and product side are equal.

$C a (O H)_{2}$ + $2 H F$ $⟶$ $2 H_{2} O$ + $C a F_{2}$

$Atoms On reactant side (LHS) On product side (RHS)$
$Ca 1 1$
$O 2 2$
$H 4 4$
$F 2 2$
Here, all the atoms on reactant and product side are same, hence, option $D$ is correct.

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