The correct option is C 5lm(2l+3a)
Given, the expression is 10l2m+15alm.
The given expression can be factorised as follows:
10l2m+15alm
=(2×5×l×l×m)+(3×5×a×l×m)
Taking out the common factors from both the terms, we get
=(5×l×m)[(2×l)+(3×a)]
=5lm(2l+3a)