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Standard XII

Chemistry

Crystal Field Split in Octahedral Complexes

Which of the ...

Question

Which of the following is the high spin complex?

[C r {(g l y)}_{3}]

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{[C o {B r}_{2} {C l}_{2} {(S C N)}_{2}]}^{3 -}

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{[F e {(C N)}_{6}]}^{3 -}

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N a [P t B r C l {({N O}_{2})}_{2} {({N H}_{3})}_{2}]

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Solution

The correct option is B $[C r {(g l y)}_{3}]$
Only complex $[C r (g l y)_{3}]$ is a high spin complex because it contains a weak field ligand and these type of ligands can not pair up the unpaired electrons while in other options there are atleast one strong field ligand. Hence,option A is correct.

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Similar questions

[F e (C N)_{6}]^{- 3}

is low spin complex but

[F e (H_{2} O)_{6}]^{+ 3}

is high spin complex. Explain.

The octahedral complex ions

[F e C l_{6}]^{3 -}

and

[F e (C N)_{6}]^{3 -}

are both paramagnetic but the former is high spin and the latter is low spin. In the low spin complex,

[F e (C N)_{6}]^{3 -}

has the d-configuration as :

The octahedral complex ions

[F e C l_{6}]^{3 -}

and

[F e (C N)_{6}]^{3 -}

are both paramagnetic but the former is high spin and the latter is low spin.
Thus, CFSE for the complexes,

[F e C l_{6}]^{3 -}

and

[F e (C N)_{6}]^{3 -}

are ___________ .

Q. (a) For the complex

{[F e {(C N)}_{6}]}^{3 -}

, write the hybridization type, magnetic character and spin nature of the complex. (Atomic number :

F e = 26

).
(b) Draw one of the geometrical isomers of the complex

{[P t {(e n)}_{2} {C l}_{2}]}^{2 +}

which is optically active.

Which of the following complexes show linkage isomerism?
(a) $[C o (N H_{3})_{5} (N O_{2})]^{2 +}$
(b) $[C o (H_{2} O)_{5} C O]^{3 +}$
(c) $[C r (N H_{3})_{5}] S C N^{2 +}$
(d) $[F e (e n)_{2} C l_{2}]^{+}$

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Which of the following is the high spin complex?

The correct option is B [Cr(gly)3]Only complex [Cr(gly)3] is a high spin complex because it contains a weak field ligand and these type of ligands can not pair up the unpaired electrons while in other options there are atleast one strong field ligand. Hence,option A is correct.

The correct option is B $[C r {(g l y)}_{3}]$
Only complex $[C r (g l y)_{3}]$ is a high spin complex because it contains a weak field ligand and these type of ligands can not pair up the unpaired electrons while in other options there are atleast one strong field ligand. Hence,option A is correct.