Which of the following is the incorrect trend of the property mentioned against it?

N O^{-} > N O > N O^{+}

[bond length]

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H_{2} > H_{2}^{+} > H e_{2}

[bond energy]

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O_{2}^{2 -} > O_{2} > O_{2}^{2 +}

[Magnetic moment]

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N O_{2}^{+} > N O_{2} > N O_{2}^{-}

[bond angle]

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Solution

The correct option is C $O_{2}^{2 -} > O_{2} > O_{2}^{2 +}$ [Magnetic moment]
Bond order of
$N O^{-} = 2.0$
$N O = 2.5$
$N O^{+} = 3.0$
Hence order of bond lengths is $N O^{-} > N O > N O^{+}$
Bond order of
$H_{2} = 1.0$
$H_{2}^{+} = 0.5$
$H e_{2} = 0$
Hence, the order of bond energy is $H_{2} > H_{2}^{+} > H e_{2}^{+}$
Bond angle of
$N O_{2}^{+} = 180^{o}$
$N O_{2} = 133^{o}$
$N O_{2}^{-} = 115^{o}$
Hence, the order of bond angles is $N O_{2}^{+} > N O_{2} > N O_{2}^{-}$
Number of unpaired electrons in
$O_{2}^{2 -} = 0$
$O_{2}^{2 +} = 0$
$O_{2} = 2$
Hence, the order of magnetic moment is $O_{2}^{2 -} = O_{2}^{2 +} < O_{2}$

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