Which of the following is the isotone of $_{16} S^{32}$ ?

_{15} P^{31}

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_{7} N^{14}

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_{18} A r^{40}

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_{17} C l^{34}

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Solution

The correct option is A $_{15} P^{31}$
Isotones are elements that are having the same number of neutrons.
$N u m b e r o f n e u t r o n s i n_{16} S^{32} = M a s s n u m b e r - N u m b e r o f p r o t o n$
$⟹ 32 - 16 = 16$

Similarly,
$N u m b e r o f n e u t r o n s i n_{15} S^{31} = M a s s n u m b e r - N u m b e r o f p r o t o n$
$⟹ 31 - 15 = 16$

Both of the elements have same number of neutrons. Hence, they are isotones.
$∴$ Option $(A)$ is correct.

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