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Writing Chemical Equations

Which of the ...

Question

Which of the following is the laboratory preparation of dihydrogen?

3 F e + 4 H_{2} O (s t e a m) \to F e_{3} O_{4} + 4 H_{2}

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2 N a + 2 H_{2} O \to 2 N a O H + H_{2}

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C a H_{2} + 2 H_{2} O \to C a {(O H)}_{2} + 2 H_{2}

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Z n + H C l (d i l .) \to Z n C l_{2} + H_{2}

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Solution

The correct option is D $Z n + H C l (d i l .) \to Z n C l_{2} + H_{2}$
In the laboratory, hydrogen gas is prepared by the action of dilute $H_{2} S O_{4}$ on granulated zinc.

$Z n + H C l (d i l .) \to Z n C l_{2} + H_{2}$

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Similar questions

What is the mechanism of following reactions in the preparation of hydrogen:

Zn+2NaOH=Na₂ZnO₂ +H₂

2Al+2NaOH+2H₂O=2NaAlO₂ +3H₂

Sn+2NaOH+H₂O=Na₂ZnO₃+ 2H₂

N a O H

100 %

I

2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}

2 H_{2} + O_{2} ⟶ 2 H_{2} O

I I

2 N a + \frac{1}{2} O_{2} ⟶ N a_{2} O

N a_{2} O + H_{2} O ⟶ 2 N a O H

C a + 2 H_{2} O \to C a {(O H)}_{2} + H_{2} ↑

C H_{3} C O O^{-} N a^{+} + 2 H_{2} O \to C H_{3} C H_{3} + 2 C O_{2} + H_{2} + 2 N a O H

2 N a + 2 H_{2} O \to 2 N a O H + H_{2}

2 N a O H + C l_{2} \to N a C l + N a O C l + H_{2} O

4 O H^{-} \to O_{2} + 2 H_{2} O + 4 e^{-}

2 C l^{-} \to C l_{2} + 2 e^{-}

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