Which of the following is the most basic compound?

B e (O H)_{2}

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C a (O H)_{2}

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B a (O H)_{2}

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M g (O H)_{2}

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Solution

The correct option is D $B a (O H)_{2}$
On moving down the group of alkaline earth metals, the basic character increases. With an increase in the ionic size, the electropositive character increases and the ionization energy decreases.

The bond polarity and the internuclear distance between metal ion and oxygen (of hydroxide ion) increases. This increases the basic character.

Hence, $B a (O H)_{2}$ is most basic.

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Similar questions

H_{2} O ?

(1) B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

(2) B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

(3) L i O H < N a O H < K O H < R b O H

(4) L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

B e (O H)_{2}, M g (O H)_{2}, A l (O H)_{3}

B (O H)_{3}

H_{2} O

B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

L i O H < N a O H < K O H < R b O H

L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

B a (O H)_{2} > S r (O H)_{2} > C a (O H)_{2} > B e (O H)_{2}

B e (O H)_{2}, M g (O H)_{2}, A l (O H)_{2}, L i O H, B (O H)_{3}, Z n (O H)_{2}

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